Universal joints with friction bearing

Version in Steel

Types

• Type EG: single, friction bearing

• Type DG: double, friction bearing

Bore codes

• Version B: without keyway

• Version K: with keyway

• Version V: with square

Steel

blank

Joint bearing areas / pins / bearing sleeves

case hardened

Version in Stainless Steel

Types

• Type EG: single, friction bearing

• Type DG: double, friction bearing

Bore code

• Version B: without keyway

• Version K: with keyway

• Version V: with square

Universal joints with needle bearing

Types

• Type EW: single, needle bearing

• Type DW: double, needle bearing

Bore codes

• Version B: without keyway

• Version K: with keyway

• Version V: with square

Steel

blank

Joint bearing areas, pins

case hardened

The permissible r.p.m. of universal joints with friction bearing DIN 808 is to a large extent dependent on the type of application such as load, duration, angular disposition as well as lubrication . For over 1000 r.p.m. universal joints with needle bearing should be used

For continuous use ample lubrication is essential. This achieved by fitting the joint with a grease filled gaiter GN 808.1 

• with other or unequal bores

Permissible r.p.m. and torque 

• Keyway DIN 6885

• Cross holes GN 110.1

• Stainless Steel characteristics 

• ISO-Fundamental Tolerances 

 

The single universal joints transfer the initial smooth rotation as an irregular rotation. One revolution of the drive shaft via single universal joint will cause the driven shaft to accelerate and decelerate twice. The extent of the irregularity depends on the operating angle ß.

In order to obtain a smooth rotation of the driven shaft two single or one double universal joint is required. In such cases where minor irregularities in the movement are acceptable or where minor operating angles are the norm a single universal joint will do.

 

 

 

Furthermore the bearings must be as close as possible to the universal joints.

For continuous operation of universal joints with friction bearings adequate lubrication is essential. If drip lubrication is not possible they should be lubricated at least once a day. It is also possible to fit the universal joint with a gaiter GN 808.1 which can be filled with oil or grease.

Universal joints with friction bearing, Type EG

 

The table shows the transferable output N and/or torques M of universal joints DIN 808, type EG (single friction bearing) in relation 

The values are only applicable to a constant speed of rotation, constant load and an operating inclination angle of max. 10°. They are not applicable to universal joints in Stainless Steel.

For larger inclination angles ß a nominal output N increased by the correction coefficient k and/or a nominal torque M has to be selected (see example below).

Conversion formular:

Torque M [Nm] = 9550 N[kW]/n [min-¹]

Output N [kW] = M [Nm] x n [min-¹]

1 kW = 1.36 PS / 1 PS = 0.736 kW

Output to be transferred N = 0.65 kW

R.p.m. n = 230 min-¹

Angle of inclination ß = 10°

Correction coefficient k = 1

Indicative output N‘= Nominal output N

Intersection point P results from 0.65 kW and 230 min-¹ (which corresponds to a torque of 27 Nm).

The next size up universal joint corresponding to point P is the model with a diameter d₁ = 25.

Example 2

Torque to be transferred M = 27 Nm

R.p.m. n = 230 min-¹

Angle of inclination ß = 30°

Correction coefficient k = 2.25

Indicative torque = 2.25 x 27 Nm = 60 Nm

Intersection point P₁ results from 61 Nm and 230 min-¹ (which is equivalent to an indicative output N = 1.47 kW).

The next size up universal joint corresponding to P₁ is the model with a diameter d₁ = 36.

 

Universal joints with needle bearing, Type EW

 

The table shows the transferable output N and/or torques M of universal joints DIN 808, type EW (single needle bearing) in relation 

The values are only applicable to a constant speed of rotation, constant load and an operating inclination angle of max. 10°.

For larger inclination angles ß a nominal output N increased by the correction coefficient k and/or a nominal torque M has to be selected (see example below).

Conversion formular:

Torque M [Nm] = 9550 N[kW]/n [min-¹]

Output N [kW] = M [Nm] x n [min-¹]

1 kW = 1.36 PS / 1 PS = 0.736 kW

Example 1

Torque to be transferred N = 5.5 kW

R.p.m. n = 2300 min-¹

Angle of inclination ß = 10°

Correction coefficient k = 1

Indicative output N‘= Nominal output N

Intersection point P results from 5.5 kW and 2300 min-¹ (which corresponds to a torque of 23 Nm).

The next size up universal joint corresponding to point P is the model with a diameter d₁ = 28.

Example 2

Torque to be transferred M = 23 Nm

R.p.m. n = 2300 min-¹

Angle of inclination ß = 18°

Correction coefficient k = 1.43

Indicative torque = 1.43 x 23 Nm = 33 Nm

Intersection point P₁ results from 33 Nm and 2300 min-¹ (which is equivalent to an indicative output N = 7.9 kW).

The next size up universal joint corresponding to P₁ is the model with a diameter d₁ = 32.